Re: BMR Workout Adjustment
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Chris
NH
Member Since:
01/19/2004 Total Posts: 852
8.5 Years Ago
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What is that BMR reduction you ask? Great question. Remember that BMR is the number of calories that you will burn if you do nothing all day. Lets say I go for a 60 minute run today. If I just show my calorie burn as BMR + workout calories burned, I'm actually cheating. Calorie estimates already take your BMR into consideration, so just adding them together would actually count my BMR value twice for the 60 minutes I'm working out. SO, I take my BMR value and divide that by 1440 (the number of minutes in a day) and then make a BMR adjustment for this amount.
In addition to this, I'm adding a box which lets you set a calorie value above and beyond BMR so you can more accurately charts your calories consumption VS loss. This box will be available in settings shortly.
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Re: BMR Workout Adjustment
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Chris
NH
Member Since:
01/19/2004 Total Posts: 852
8.5 Years Ago
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To simplify matters on the home page chart: I've changed the way this data displays. Here is the latest handbook entry for the chart:
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We are using the Harris Benedict formula to determine the number of calories you will burn before working out. This calculation is BMR * 1.2. This number will show as a negative number on your home page chart because these are calories you are expending.
Your workout value INCLUDES your BMR in the total. Therefore, we have removed the BMR value from your calories burned (the value you would have burned had you not worked out) in order to provide a more accurate measurement of calorie expenditure. |
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Re: Re: BMR Workout Adjustment
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Chris
NH
Member Since:
01/19/2004 Total Posts: 852
8.5 Years Ago
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I may need to find a better way to display this. A negative total means you are expending more calories than you are burning. So your daily calorie change to your body would be -575
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Re: BMR Workout Adjustment
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Stephen
FL
Member Since:
11/24/2019 Total Posts: 1
4.0 Years Ago
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When should I choose to add something to my precalculated BMR measurement? You mention it doesn't take into consideration "lean mass" which I don't understand. |
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